Time for another Project Euler problem. This problem is somewhat simple, but we need to dive into some SQL to solve it!

## Problem 4:

### Largest Palindrome Product

A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 × 99.

Find the largest palindrome made from the product of two 3-digit numbers.

DECLARE lower_range PLS_INTEGER := 100; upper_range PLS_INTEGER := 999; product VARCHAR2(1000); reverse_product VARCHAR2(1000); answer PLS_INTEGER := 0; BEGIN FOR x IN REVERSE lower_range..upper_range LOOP FOR y IN REVERSE lower_range..upper_range LOOP product := x * y; --we can exit as our y value is too low IF product < answer THEN exit; END IF; SELECT REVERSE(product) INTO reverse_product FROM dual; IF product = reverse_product AND product > answer THEN answer := product; EXIT; END IF; END LOOP; END LOOP; dbms_output.put_line(answer); END; --output: 906609

This solution is pretty easy to understand if you can wrap your mind around why we use an inner and outer loop. We speed things up in the inner loop by exiting when our `y`

value has gotten so small that our `product`

would no longer be greater than our current `answer`

, saving us a lot of time.

PL/SQL has no built-in `REVERSE`

function, but rather than write a subfunction I opted to use the SQL REVERSE call, which works exactly as we need it to.

Questions or comments? Feel free to leave them below or reach out to me on Twitter!